Question

Robert, a stuntman, projects himself from a height of 50.0 meters in a horizontal direction. He safely lands at a horizontal distance of 100.0 meters. Calculate the horizontal velocity with which Robert projected himself.

Answer 1

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Answer 2

first use the vertical distance to calculate how long he was in the air. we can use delta y = (1/2)at^2 where delta y is the vertical distance travelled (50.0 m), a is the accelration due to gravity (9.81m/s^2), and t is time. solve for time. from there, you can calculate the horizontal velocity by dividing the horizontal distance 100.0 m by the time in the air.