Question

PLSS HELP ASAP!!!

1) What is the equation in point slope form of the line that passes through the point (1 , 8) and (2 , 10)?

y+8=2(x+1)

y-8=2(x-1)

2x-y=7

y=2x-7


2) If you have points (1,1) and (5,9) on a graph, what is the point slope form?


y-1=2(x-1)

y+1=2(x+1)



3) If you have points (3,6) and (2,1) on a graph, what is the equation of the line in standard form?


7x+y=13

y-8=7(x-3)

7x-y=13



4) If you have points (1,4) and (-1,2) on a graph, what is the equation of the line in slope intercept form?

2x-y=-3

y=x+3

(more below!)

Answer 1

On the second one, the points are (2,15) and (0,5)....

Answer 2

@narad this should be light work for you

Answer 3

r they online rn??

Answer 4

yeah but idk if he’s active

Answer 5

ok ty!

Answer 6

if not I could help you with some

Answer 7

@supie

Answer 8

okay so for question 1, the equations are written in point slope form, y-y1=x(x-x1)

so i would just find the equation that matches y1 and x1 with (1,8) and (2,10)

Answer 9

ykwim or no?

Answer 10

ya i do!

Answer 11

nvm i read the question wrong

Answer 12

oh no!

Answer 13

@aiden3j

Answer 14

okay Kacchan do you now how to find a slope?

Answer 15

urm kinda kinda not (sorry its been a while since we've worked on it)

Answer 16

ok so the first three steps
Locate two points on the line whose coordinates are integers.
Starting with the point on the left, sketch a right triangle, going from the first point to the second point.
Count the rise and the run on the legs of the triangle.
Take the ratio of rise to run to find the slope. m=riserun.

Answer 17

on the 1st one??

Answer 18

m=riserun=ΔyΔx
m=y2−y1x2−x1
m=10−82−1
m=21
m = 2

is this right @aiden3j ??

Answer 19

The point slope form of this equation would be y - 8 = 2(x - 1)

Answer 20

the slope formula.

m = (y2 - y1)/(x2 - x1)

m = (10 - 8)/(2 - 1)

m = 2/1

m = 2

Answer 21

thanks @lovemelee i have to go for a bit

Answer 22

oh?

Answer 23

hold on imma close this and fix it! i answered some

Answer 24

just take your time with it glad to help :)

Answer 25

oh ok

Answer 26

ive just posted it!

Answer 27

k