Question

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Answer 1

The general quadratic equation is
\[a x^{2}+bx+c=0\]
Here, we have
\[x^{2}-4x+3=0\]
Therefore,
\[a=1\]
\ and \[c=3\] The solution is \[x=\frac{ -b \pm \sqrt{b^{2}-4ac} }{ 2a }\] Apply the formula and you'll get the 2 solutions.