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@luigi0210 can u help me again
You're gonna need to use this again: \[\Large A= \frac{\theta}{360}*\pi*r^2 \] Given r = 13 and theta = 7.4 \[\Large A=\frac{7.4}{360}*\pi* 13^2 \]
i got 30.2068 as my answer @luigi0210
@axie
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bro i literally just got on.
yeah i think this is a jhonny question...
No, it's not 30.2. Try again
um ok so i round 30.2 to the nearest 10th and i would get that number to stay the same
I think you multiplied it out wrong:
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ok but since i round my answer to the nearest 10th it would be 11 right
To the nearest "tenth" would mean it rounds to 10.9 cm^2
o so its 10.9
tenths are the 0.X numbers
@luigi0210 so it would be 10.9 for my answer
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