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I say the last one, where x=9 and y=7 7*9=63 2(9) + 3 = 21 7-4= 3 21*3= 63
You just gotta set the sides equal: \[\large y-4=7\] and \[\large 2x+3=9\] Give you: x= 3, and y =11
@destwt wrote:
I say the last one, where x=9 and y=7
7*9=63
2(9) + 3 = 21
7-4= 3
21*3= 63
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what abt thiss can someone help me with this?
@luigi0210 wrote:
You just gotta set the sides equal:
\[\large y-4=7\]
and
\[\large 2x+3=9\]
Give you:
x= 3, and y =11
luigi come back pls
Since the hypothenuse for triangle ABC is 7, it cannot be congruent to triangle DEF. The hypothenuse has to be larger than the 2 side lengths, since it is a right triangle. So "no, because the hypothenuses must have different lengths."
@luigi0210 wrote:
Since the hypothenuse for triangle ABC is 7, it cannot be congruent to triangle DEF.
The hypothenuse has to be larger than the 2 side lengths, since it is a right triangle.
So "no, because the hypothenuses must have different lengths."
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What are the answer choices? Cause I don't know the theorems by memory
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luigi
i did it
@luigi0210 wrote:
What are the answer choices? Cause I don't know the theorems by memory
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