Question

D5.4. A copper conductor has a diameter of 0.6 in. and it is 1200 ft long.

Assume that it carries a total de current of 50 A(a) Find the total resistance of

the conductor(b) What current density exists in it? (c) What is the de voltage

between the conductor ends? (d) How much power is dissipated in the wire?

Ans. 0.035 2/2.74 * 10 ^ 5 * A / (m ^ 2) 1.73 V86.4 W

Answer 1

(a)
\[ R=\rho \frac{ L }{ A }\]
(b)
\[Current density=\frac{ I }{ A }\]
(c)
\[Voltage = RI\]
(d)
\[Power = RI ^{2}\]

Answer 2

Lol

Answer 3

@hyper