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with what exactly?
ayo
Hence, the equation x^4 + x^2 + 1 = 0 has no real solutions. @xxcelestxx
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This will give us four complex solutions for x, which are the square roots of the two values of y. The solutions are not real numbers, and they are complex conjugates of each other. The exact form of the solutions will involve complex numbers and can be expressed using complex square roots or, more commonly, in polar form.
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