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d = √((x^2-x^1)^2 + (y^2-y^1)^2) Step by step procedure: Find the difference between coordinates: (x^2-x^1) = (-2 - -8) = 6 (y^2-y^1) = (2 - 10) = -8 Square the results and sum them up: (6)^2 + (-8)^2 = 36 + 64 = 100 Now Find the square root and that's your result: Exact solution: √100 = 10 Approximate solution: 10 I hope I could help ^_^
@oliver69 wrote:
d = √((x^2-x^1)^2 + (y^2-y^1)^2)
Step by step procedure:
Find the difference between coordinates:
(x^2-x^1) = (-2 - -8) = 6
(y^2-y^1) = (2 - 10) = -8
Square the results and sum them up:
(6)^2 + (-8)^2 = 36 + 64 = 100
Now Find the square root and that's your result:
Exact solution: √100 = 10
Approximate solution: 10
I hope I could help ^_^
No problem sweetie
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