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Mathematics 16 Online
ihatelifeFS420:

math

ihatelifeFS420:

ihatelifeFS420:

@oliver69

ihatelifeFS420:

that is not right

ihatelifeFS420:

@curriful @oliver69

xcoledd1:

what type of math

curriful:

is it x= 9,1

jayfafr:

any thoughts?

ihatelifeFS420:

@curriful wrote:
is it x= 9,1
yes

ihatelifeFS420:

I had the 1 right but this math confuses me

xcoledd1:

bye

jayfafr:

its 9 and 1

curriful:

forgot i cant give answer straight up oml

ihatelifeFS420:

ihatelifeFS420:

I have 2 as one of them

xcoledd1:

subtract 36 from 100 then square root it and you'll get the answer

jayfafr:

its 2 and -2

ihatelifeFS420:

@jayfafr wrote:
its 2 and -2
how did u get that

jayfafr:

Subtracting 36 from both sides find x then take the sixth root of both sides

jayfafr:

∣x∣=2 this means that x could either be 2 of -2

jayfafr:

so the real soultions to the equation are 2 and -2

ihatelifeFS420:

jayfafr:

first mupitly both sides by 3

jayfafr:

to get rid of the fraction

jayfafr:

then you get x^4=81

jayfafr:

then fourth root both sides

jayfafr:

and it gets 3

jayfafr:

since the abouslte value of 3 is 3

jayfafr:

and the abousle value of -3 is also 3

jayfafr:

means the soultion is 3 and -3

ihatelifeFS420:

thank you so one last question sorry if i'm bothering u with questions

jayfafr:

if my math is correct that should be the answer

curriful:

@ihatelifefs420 wrote:
Move all terms not containing x to the right side of the equation. Subtract 36 from both sides of the equation. x^6=100−36 Subtract 36 from 100. x^6=64 Take the specified root of both sides of the equation to eliminate the exponent on the left side. x=±^6√64 Simplify ±^6√64. Rewrite 64 as 2^6. x=±^6√2^6 Pull terms out from under the radical, assuming positive real numbers. x=±2 The complete solution is the result of both the positive and negative portions of the solution. First, use the positive value of the ± to find the first solution.x=2 Next, use the negative value of the ± to find the second solution. x=−2 The complete solution is the result of both the positive and negative portions of the solution. x=2,−2

ihatelifeFS420:

jayfafr:

multiply both sides by 6 to get rid of the fraction

jayfafr:

when you do that you get x^3=-216

jayfafr:

cube root both sides

jayfafr:

you get this ∣x∣=-6

ihatelifeFS420:

thank u so much

jayfafr:

there is no real soultion

jayfafr:

its not 6 nooooo

ihatelifeFS420:

yeah ik it's -6

jayfafr:

no theres no solution

jayfafr:

real solution to this equation is 1/6x^3=-36

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