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Mathematics 21 Online
daddylala:

Help

daddylala:

Midnight97:

Let me see what I can do

daddylala:

okay

daddylala:

@midnight97 wrote:
Let me see what I can do
??

whyjustwhy:

Umm, I don't think that would be used in irl

Midnight97:

@daddylala wrote:
@midnight97 wrote:
Let me see what I can do
??
I am working it out rq

daddylala:

@whyjustwhy wrote:
Umm, I don't think that would be used in irl
i think its because your probably in a lower grade

daddylala:

@midnight97 wrote:
@daddylala wrote:
@midnight97 wrote:
Let me see what I can do
??
I am working it out rq
ok

Midnight97:

So we have a formula

daddylala:

is it too hard

Midnight97:

Midnight97:

That's the formula I am now working it all out

daddylala:

okay

Midnight97:

for the 27s inside the brackets so in this case the powers are added we need both of the formulas to solve the problem, we need both of the formulas to solve the problem first we apply the second one and then the first a is 27 x is 5 and y is -2

Midnight97:

daddylala:

thank you❤

Midnight97:

Now add the 5 and -2

daddylala:

ok

Midnight97:

which is 3 so that means it will be 27^3

Midnight97:

I am thinking rq there is more to it

Midnight97:

I'm back sorry I had to deal with something

daddylala:

okay

Midnight97:

now it's (27^3)^-1 we need to apply the power -1 using the first formula

daddylala:

ok

Midnight97:

daddylala:

thats the answer?

Midnight97:

@daddylala wrote:
thats the answer?
still working on it

Midnight97:

So I am going to skip a step so we now have 27^-3

Midnight97:

Which gives us 27^-4 x 27^-3

Midnight97:

Once again add -4 + -3=-7 that will make 27^-7 which is also your answer

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