The probability of event A occurring is 0.32, the probability of event B occurring is 0.11, and the probability of events A and B occurring is 0.02. Determine P(A|B).

0.035
0.063
0.182
0.430

Question

The probability of event A occurring is 0.32, the probability of event B occurring is 0.11, and the probability of events A and B occurring is 0.02. Determine P(A|B).

0.035
 0.063
 0.182
 0.430

Phantomdex · Answer

@aubree

Phantomdex · Answer

Sorry for the pink I just need help in math again and jay isn't on TwT

Phantomdex · Answer

@jayfafr

OLIVER69 · Answer

What you're solving for? 
    The probability of A given V

What's given in the problem?
     The probability of event A occurring is 0.32
     The probability of event B occurring is 0.11
     The probability of events A and B occurring is 0.02

Helpful Information:
The conditional probability of A given B is P{A|B) = P(A ∩ B)/P(B)

Step 1: Substitute P(A  ∩ B) = 0.02 and P(B) = 0.11 into the conditional probability.

Step 2: Simplify the fraction to 0.02/0.11

Solution is 0.182

So the probability of A given B is approximately 0.182

(I hope this helps you)

Phantomdex · Answer

@oliver69 wrote:

What you're solving for? The probability of A given V What's given in the problem? The probability of event A occurring is 0.32 The probability of event B occurring is 0.11 The probability of events A and B occurring is 0.02 Helpful Information: The conditional probability of A given B is P{A|B) = P(A ∩ B)/P(B) Step 1: Substitute P(A ∩ B) = 0.02 and P(B) = 0.11 into the conditional probability. Step 2: Simplify the fraction to 0.02/0.11 Solution is 0.182 So the probability of A given B is approximately 0.182 (I hope this helps you)

Thank you very much and yes it did!

jhonyy9 · Answer

@oliver69 wrote:

What you're solving for? The probability of A given V What's given in the problem? The probability of event A occurring is 0.32 The probability of event B occurring is 0.11 The probability of events A and B occurring is 0.02 Helpful Information: The conditional probability of A given B is P{A|B) = P(A ∩ B)/P(B) Step 1: Substitute P(A ∩ B) = 0.02 and P(B) = 0.11 into the conditional probability. Step 2: Simplify the fraction to 0.02/0.11 Solution is 0.182 So the probability of A given B is approximately 0.182 (I hope this helps you)

Explaned perfect, good work