Help is needed

Question

Help is needed

Midnight97 · Answer

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toga · Answer

A: Let's denote the length of the field with 'l'.

The perimeter of a rectangle is given by the formula:

perimeter = 2(length + width)

Substituting the given values, we get:

332 = 2(l + 67)

Simplifying the equation, we get:

166 = l + 67

l = 166 - 67

l = 99

Therefore, the length of the rectangular field is 99 meters.

Midnight97 · Answer

@toga wrote:

A: Let's denote the length of the field with 'l'. The perimeter of a rectangle is given by the formula: perimeter = 2(length + width) Substituting the given values, we get: 332 = 2(l + 67) Simplifying the equation, we get: 166 = l + 67 l = 166 - 67 l = 99 Therefore, the length of the rectangular field is 99 meters.

Thank you

toga · Answer

B: denote the width of the painting with 'w'.

The area of a rectangle is given by the formula:

area = length x width

Substituting the given values, we get:

8148 = 97 x w

Simplifying the equation, we get:

w = 8148 / 97

w = 84

Therefore, the width of the rectangular painting is 84 cm.

Midnight97 · Answer

@toga wrote:

B: denote the width of the painting with 'w'. The area of a rectangle is given by the formula: area = length x width Substituting the given values, we get: 8148 = 97 x w Simplifying the equation, we get: w = 8148 / 97 w = 84 Therefore, the width of the rectangular painting is 84 cm.

Thanks again

Midnight97 · Answer

I do have another one like this I need help with

toga · Answer

@midnight97 wrote:

I do have another one like this I need help with

ok

Midnight97 · Answer

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Midnight97 · Answer

I am just gonna make a new post -.-

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