Question

I'm slow help pls

Answer 1

D
use loga (x/y)=loga(x)-loga(y) to expand the experssion >> log6(a^4)-log6(b^2)
log6 (a^4)-log6 (b^2)
use loga(b^c)=cx loga (b) to transform the experssion >>> 4 log6 (a)-log6 (b^2)
use loga (b^c)= c x loga (b) to transform the experssion >>> 4 log6 (a) - 2 log6 (b)
solution : 4 log6 (a) - 2 log6 (b)

Answer 2

What bb cherry said ^

\[\large log_a(x) - log_a(y) = log_a\frac{x}{y} \]

\[\Large log_a(x^y) = y*log_a(x) \]

Answer 3

thank the heavens