Question

helpp

Answer 1

If it helps you can convert the '2y' into a fraction with a denominator of 8, as such:

\(\large \frac{5}{8} y -\frac{3}{8} y + \frac{16}{8} y \)

Now you can add them together

\(\Large \frac{5-3+16}{8} y \)

Answer 2

ohh ty