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solve Quadraic equations by taking the square root 1). x2 =49 2).x2=73 3). x2+5=69 Help me please
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1). x=7 and x=-7 2). ? 3). x=8 x=-8
@blkops77 wrote:
1). x=7 and x=-7
2). ?
3). x=8 x=-8
-Assuming x2 = x^2- 1) x^2 = 49 sqrt(x^2) = sqrt(49) x = 7 2) x^2 = 73 sqrt(x^2) = sqrt(73) The sqrt of 73 is an unfactorable number and is not a perfect square, so it must remain as sqrt(73) unless you are explicitly told to estimate/round so x = sqrt(73) 3) x^2 + 5 = 69 x^2 + 5 - 5 = 69 - 5 x^2 = 64 sqrt(x^2) = sqrt(64) x = 8 --The negative values of the afformentioned x solutions also apply, as a -# * a -# = a positive #
@luigi0210 wrote:
@blkops77 wrote:
1). x=7 and x=-7
2). ?
3). x=8 x=-8
@blkops77 wrote:
simple math atleast for me, idk wha math you guys do in school or wtv
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