Question

solve Quadraic equations by taking the square root
1). x2 =49
2).x2=73
3). x2+5=69
Help me please

Answer 1

1). x=7 and x=-7
2). ?
3). x=8 x=-8

Answer 2

-Assuming x2 = x^2-

1) x^2 = 49
sqrt(x^2) = sqrt(49)
x = 7

2) x^2 = 73
sqrt(x^2) = sqrt(73)
The sqrt of 73 is an unfactorable number and is not a perfect square, so it must remain as sqrt(73) unless you are explicitly told to estimate/round
so x = sqrt(73)

3) x^2 + 5 = 69
x^2 + 5 - 5 = 69 - 5
x^2 = 64
sqrt(x^2) = sqrt(64)
x = 8

--The negative values of the afformentioned x solutions also apply, as a -# * a -# = a positive #

Answer 3

simple math atleast for me, idk wha math you guys do in school or wtv