Question

math help pls

Answer 1

A quadratic equation is given by the formula ax2+bx+c=0ax^2 + bx + c = 0ax
2
+bx+c=0. If the equation is 2x2−4x−6=02x^2 - 4x - 6 = 02x
2
−4x−6=0, determine the values of xxx using the quadratic formula.

Answer 2

\[2x^2-4x-6=0\]
divide by 2
\[x^2-2x-3=0\]
\[x=\frac{ -(-2)\pm \sqrt{(-2)^2-4(1)(-3)} }{ 2\times1 }=\frac{ 2\pm \sqrt{4+12}} }{ 2}\]
\[x=\frac{ 2\pm 4 }{ 2}\]
either
\[x=\frac{ 2+4 }{ 2 }=\frac{ 6 }{ 2 }=3\]
or
\[x=\frac{ 2-4 }{ 2 }=\frac{ -2 }{ 2}=-1\]

Answer 3

Ai

Answer 4

i suck at math

Answer 5

.,.