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A quadratic equation is given by the formula ax2+bx+c=0ax^2 + bx + c = 0ax 2 +bx+c=0. If the equation is 2x2−4x−6=02x^2 - 4x - 6 = 02x 2 −4x−6=0, determine the values of xxx using the quadratic formula.
\[2x^2-4x-6=0\] divide by 2 \[x^2-2x-3=0\] \[x=\frac{ -(-2)\pm \sqrt{(-2)^2-4(1)(-3)} }{ 2\times1 }=\frac{ 2\pm \sqrt{4+12}} }{ 2}\] \[x=\frac{ 2\pm 4 }{ 2}\] either \[x=\frac{ 2+4 }{ 2 }=\frac{ 6 }{ 2 }=3\] or \[x=\frac{ 2-4 }{ 2 }=\frac{ -2 }{ 2}=-1\]
Ai
i suck at math
.,.
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