ihy:
Two particles A and B having different masses are projected from a tower with same speed. A is project vertically upward and B vertically downward. On reaching the ground... a) Velocity of A is greater than that of B b) Velocity of B is greater than that of A c) Both A and B attain the same velocity d) The particle with the larger mass attains higher velocity
breiadabrattzz:
Do you know the formula??
ihy:
breiadabrattzz:
It is
ihy:
breiadabrattzz:
Let’s carefully analyze step by step
ihy:
breiadabrattzz:
Both A and B are projected from the same height (top of tower). Both are given the same initial speed (u). A goes vertically upward, while B goes downward. The acceleration on both is gravity (g) downward. Air resistance is neglected (since it’s not mentioned).
ihy:
breiadabrattzz:
Particle A Initial velocity = –u (taking downward as positive direction). It goes up, stops momentarily, then falls down past the tower, gaining speed. Using the kinematic equation: v^2=u^2+2gh
ihy:
ihy:
Is the answer C?
breiadabrattzz:
Yes
ihy:
YAY!
ihy:
Much appreciated :)
breiadabrattzz:
Your welcome.
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ihy:
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ihy:
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ihy:
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ihy:
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ihy:
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ihy:
I hope you guys stay safe as y'all go out for Halloween tomorrow night!
