Question

Helpppp

Answer 1

Its multiplying probabilities with independent and dependent

Answer 2

this looks so confusing...

Answer 3

its probabiliy

Answer 4

For #2:

a) Throwing a 4 with one die and a 6 with another
Independent (one die doesn’t affect the other)
b) Picking a 7, keeping it, and then picking a jack
Dependent (card not replaced)
c) Flipping a tail with a coin and rolling a 4 with a die
Independent
d) Drawing a spade and then a heart without replacement
Dependent
e) Picking two black marbles after replacing the first
Independent

For #3:

a) Both marbles are red: (6/13)(6/13) = 36/169

b) Both marbles are blue: (3/13)^2 = 9/169

c) First red, second blue: 6/13 x 3/13 = 18/169

d) Neither is red (white or blue both times): (7/13)^2 = 49/169



For #4:


There's 26 total letters
Vowels = A, E, I, O, U = 5
Consonants = 21

a) Both vowels: 5/26 x 4/25 = 2/25

b) Both consonants: 21/26 x 20/25 = 42/65




For #5:


Number of hands in favor: 4^5 =1,024
Total 5-card hands: (52 5) = 2,598,960

Probability: 1024/2,598,960 = 64/162,435



For #6:


Even then tails, then odd: 3/6 x 1/2 x 3/6 = 1/8



For #7:

a) One of each: 7/17 x 6/16 x 4/15 = 7/170

b) Three milk chocolates: 7/17 x 6/16 x 5/15 = 7/136



For #8:

P(outdoor) = 0.65
P(appetizer) = 0.60

So we'll use this formula: P(A∪B) = P(A) +P(B) − P(A)P(B)

Then we'll plug in the numbers: 0.65 + 0.60 − (0.65)(0.60) = 0.86

So your final answer is 0.86

Answer 5

Sorry it's so long :sob: