Ask
your own question, for FREE!
Mathematics
33 Online
does anyone understand this finding the real solution? the 3 and 2 are exponets ???x^3/^2 -27=0
Still Need Help?
Join the QuestionCove community and study together with friends!
Hm. What do you mean? The real solution of each is the appropriate root. e.g.: $$ x^2 - 27 = 0 $$ $$ x^2 = 27 $$ $$ x = \pm \sqrt{27} $$
Ah, sorry, misunderstood. You have \(x^{\frac{3}{2}}\) In that case the process is similar, but you have to remember that \(\sqrt{x}\) is the same as \(x^2\), so \(x^{\frac{3}{2}}\) is really the same as \(\sqrt{x^3}\). So, you end up with: $$ \sqrt{x^3} = 27 $$ You can reverse the square root by squaring and the cube by taking the cubed root.
I meant \(\sqrt{x}\) is the same as \(x^{\frac{1}{2}}\).
Thanks so much:)
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
XShawtyX:
Helpud83dude4f All this graphing shi hurts my head like how tf do u do this????
Jasonisyours:
What were the key causes of the French Revolution in 1789?
brianagatica14:
A phone company charges $2 for the first five minutes of a phone call and 30 cents per minute thereafter.
CherryLover:
not sure if ya'll hear of this but last year there was this girl and her name is Aubreigh Wyatt and she was bullied by a group of people and they hated her
ctomk3743:
It's another song I had in mind (please no negative comments) I walk through the rain at night as the wind blows hard and the rain pours down on me.
2 hours ago
1 Reply
1 Medal
2 hours ago
2 Replies
4 Medals
1 hour ago
5 Replies
3 Medals
2 hours ago
41 Replies
3 Medals
1 day ago
8 Replies
7 Medals