find the roots of this equation 2x^3-3x^2+12x+9=0 ??
show the procedure without using calculator??

Question

shadowfiend · Answer

Heh. This is a pretty tough one. You have to factor the equation, but I've been having some trouble doing that.

anonymous · Answer

The rational root theorem says that any rational (fractional) root of the equation will be of the form p/q, where p is a factor of 9 (so +/- 1, 3, 9) and q is a factor of 2 (so +/- 1, 2). That gives a bunch of choices to try, but they are the only choices.

Use synthetic division to see which root(s) divide in to the original without a remainder.

anonymous · Answer

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anonymous · Answer

I have no idea how to do this but see if this will help you. By the looks of it the root looks really ugly. http://www.wolframalpha.com/input/?i=2x^3-3x^2%2B12x%2B9