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Mathematics
OpenStudy (anonymous):
In 5 days a 10.0mg sample of radioactive material decays to 3.5mg. based on this information what is the half life?
8 years ago
OpenStudy (shadowfiend):
Hm. Do you have an exponential decay function to work with?
8 years ago
OpenStudy (anonymous):
Current quantity = original quantity times e raised to the power (elaspsed time / half life), if I remember correctly, or \[Q=Q _{0}e ^{t/h}\]. Plug in and solve for half life; you have everything else you need.
8 years ago
OpenStudy (anonymous):
Oops. I think my exponent is missing a k, specifically -ln(2). So the correct exponent, if I'm right, is e^(-t ln2)/h
8 years ago
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