How do we determine x=(4-y^2)^1/2? http://tutorial.math.lamar.edu/Classes/CalcII/HydrostaticPressure.aspx <--diagram in example 2. Thx!
I figured it out. :D
Awesome. If you get a chance to post a quick summary I'm sure that would help others :)
Pythagorean theorem - triangle using r=2 for hypotenuse and y-subi for one side. Which will leave the remaining side x to the above equation after solving.