How do I differentiate ln(xy^2)=y

8 years agodifferentiate y with respect to x, i presume?

8 years agoyes with respect to x

8 years agomy first instinct says try implicit differentiation, but u substitution could be an option.

8 years agoIt is an implicit differentiation problem, however I can't figure out what ln(xy^2) differentiates to... if I could figure that out I could simplify it algebraically no problem

8 years ago\[\frac{\delta y}{\delta x} \ln(xy^2) = y^2 * \frac{\delta}{\delta x} (x)\]

8 years agoso since we are differentiating with respect to x, we can consider any 'y' portions to be constant and proceed as such.

8 years agobut for implicit differentiation, you have to include a dy/dx term when you take the derivative

8 years agothank you! That helps me understand how to finish the problem much better!

8 years agoThe derivative is implicit, but it also requires chain rule (because xy^2 is a function) and, later, product rule (x times y^2). The right hand side is just dy/dx. That help?

8 years ago