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OpenStudy (anonymous):

how do I find the integral of sqrt(16x - x^2)?

OpenStudy (anonymous):

Not sure I could do it by hand anymore, but in a book of integrals, we find INT(SQRT(2ax-x^2)dx. That's your integral, with a=8. The answer is quite lengthy; too long for me to type. Worst case, get it from or

OpenStudy (anonymous):

Like LBickford the answer is kind of complicated but here are the steps. (1) Complete the square inside the square root--SQRT(64- (x-8)^2) (2) Use u substitution-- u=x-8 (3) Use z substitution-- z = \[\sin \theta\]

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