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OpenStudy (anonymous):
I have the question 1-2 sin^2ø/sinø cosø = cot ø tan ø
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OpenStudy (anonymous):
I converted the cot ø to cos ø over sin ø and the tan ø to sin ø/ cosø
OpenStudy (shadowfiend):
Hm. The right side is cot ø tan ø or is it cot ø + tan ø?
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