how can you resolve this pro: 3(4-x)=5-x+ 6(2-x)

Question

anonymous · Answer

All you need to do is distribute the multiplication, then group together like terms.

$$ 3(4-x) \Rightarrow 12-3x \
6(2-x) \Rightarrow 12 - 6x \
\Rightarrow 12-3x = 5-x+12-6x\
\Rightarrow 12-5-12 = 3x-x-6x\
\Rightarrow -5 = -4x\
\Rightarrow x = \frac{5}{4} $$

anonymous · Answer

$$3(4-x) \Rightarrow 12-3x\
6(2-x) \Rightarrow 12-6x\
\Rightarrow 12-3x = 5-x+12-6x\
\Rightarrow 12-5-12 = 3x-x-6x\
\Rightarrow -5 = -4x \
\Rightarrow x = \frac{5}{4}$$

shadowfiend · Answer

Let's try this:

$$\begin{align} &3(4-x) \Rightarrow 12-3x\ &6(2-x) \Rightarrow 12-6x\ &\Rightarrow 12-3x = 5-x+12-6x\ &\Rightarrow 12-5-12 = 3x-x-6x\ &\Rightarrow -5 = -4x \ &\Rightarrow x = \frac{5}{4} \end{align}$$