OpenStudy (anonymous):

d^2f/dx^2+(ax+b)df/dx+cf=const Could someone know an easier way to solute this ode?

7 years ago
OpenStudy (anonymous):

7 years ago
OpenStudy (anonymous):

What do you mean with "reduce to a quadratic " ? Do you mean, I should transform it in dies form d^2f/dx^2+bdf/dx+cf=const-(ax+b)df/dx .

7 years ago
OpenStudy (anonymous):

if you allow the coefficients to be the terms for a quadratic, i.e. $r ^{2}+(ax+b)r+c = 0$ then use the quadratic formula $(-b \pm \sqrt{b ^{2}-4ac})/2a$ to find r such that it satisfies the ODE

7 years ago
OpenStudy (anonymous):

but you can't do that because r is also a function of x. r=r(x)

7 years ago
OpenStudy (anonymous):

no you treat it as a constant

7 years ago
OpenStudy (anonymous):

what do you have so far for your work and/or proof?

7 years ago
OpenStudy (anonymous):

I though about another approach, please, have a look on this site, http://www.ltcconline.net/greenl/courses/204/PowerLaplace/seriesSolutions1.htm

7 years ago
OpenStudy (anonymous):

did you figure out the u substitution? if you did then it should follow...but i honestly don't think you need to use series for it

7 years ago
OpenStudy (anonymous):

I figure it, but it seems to be really complicatet to have a serie solution.

7 years ago
OpenStudy (anonymous):

Because of the non-constant coefficients and it become very ugly

7 years ago
OpenStudy (anonymous):

can I send you a copy of my work?

7 years ago

7 years ago
OpenStudy (anonymous):

yeah i would like to see it

7 years ago

7 years ago
OpenStudy (anonymous):

You could try using laplace transforms. It would turn the the 2nd order ODE into a 1st order ODE. Usually 1st order ODE are easier to solve. Look at the example here http://tutorial.math.lamar.edu/Classes/DE/IVPWithNonConstantCoefficient.aspx

7 years ago
OpenStudy (anonymous):

i think that's what he was trying to do

7 years ago
OpenStudy (anonymous):

here is a copy http://imgur.com/9y7hu

7 years ago
OpenStudy (anonymous):

7 years ago
OpenStudy (anonymous):

ok yeah now it is better to see... i think that it works, after simplifying then you can solve the ODE. but i think its already simplified...

7 years ago
OpenStudy (anonymous):

but when it is already simplified, what is the result now?

7 years ago
OpenStudy (anonymous):

I'm gonna use matlab to solve,

7 years ago
OpenStudy (anonymous):

you can also check your answer on this website: http://www.wolframalpha.com/input/?i=y''+%2B+(ax%2Bb)y'%2Bcy+%3D+f The answer seems a bit complicated :\

7 years ago
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