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Mathematics 104 Online
OpenStudy (anonymous):

is the series (n=1 to infinity) for: -1/(x+1) divergent or convergent, and how do you prove it?

OpenStudy (anonymous):

is it (-1)^{n}/(x+1) ? otherwise the answer would be -1/(x+1) since the function or sequence you are looking at does not depend on n.

OpenStudy (anonymous):

\[(-1)^{n}/(x+1)\]

OpenStudy (anonymous):

Sorry, I meant for -[(1)/(n+1)], I shouldn't have included x. Since this is in general harmonic form, can I say it is divergent? Thanks.

OpenStudy (anonymous):

yes. look at limit comparison test

OpenStudy (anonymous):

actually, if you look at the sequence, if the entire thing is negative, then you can just do comparison test to harmonic series. just take absolute value of your sequence first

OpenStudy (anonymous):

That makes sense, thanks a bunch :D

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