OpenStudy (anonymous):

is the series (n=1 to infinity) for: -1/(x+1) divergent or convergent, and how do you prove it?

7 years ago
OpenStudy (anonymous):

is it (-1)^{n}/(x+1) ? otherwise the answer would be -1/(x+1) since the function or sequence you are looking at does not depend on n.

7 years ago
OpenStudy (anonymous):

\[(-1)^{n}/(x+1)\]

7 years ago
OpenStudy (anonymous):

Sorry, I meant for -[(1)/(n+1)], I shouldn't have included x. Since this is in general harmonic form, can I say it is divergent? Thanks.

7 years ago
OpenStudy (anonymous):

yes. look at limit comparison test

7 years ago
OpenStudy (anonymous):

actually, if you look at the sequence, if the entire thing is negative, then you can just do comparison test to harmonic series. just take absolute value of your sequence first

7 years ago
OpenStudy (anonymous):

That makes sense, thanks a bunch :D

7 years ago
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