50000-x x is the amount of in $ ann invested in the account that pays 2.5% annual interset

9 years agook what are you trying to solve for?

9 years agoshe invests 50,000 in two interst bearing accounts one pays 2.5 % interst and the second 3.75% at the end of one year the interest ann has earned on these is 1656.25 $ how much she invest in each of the accounts

9 years agook got it!

9 years agoso what in an interest account, each year you earn the % of interest according to your original investment

9 years agoso from the first account, she will earn 2.5% of 50,000

9 years agofrom the second account, she will earn 3.75% of 50,000

9 years agoor sorry, bad first assumption

9 years agoso we have two equations based on this information:

9 years agoboth involve amounts x and y

9 years agowe know that .025x + .0375y = 1656.25

9 years agothat is, the interest earned between the two accounts adds up to 1656.25, and by definition .025 of X is earned, and .0375 of y is earned in that year

9 years agothe other thing we know is that the total amount she invests is 50,000, so x + y = 50,000

9 years agonow since you have two variables, and two equations, you can use substitution to solve this

9 years agoso using the second equation, we know that y = 50,000 - x

9 years agoi have to give a vebal descritpion of 50000-x

9 years agoI'm not sure what you mean by verbal description

9 years agobut we know that 50000 - x is the amount invested in one of the banks

9 years agoit says give a verbal description of what each of the follwoing expression represetn in the context of the problem letting x=2.5 %. 50,000 is the interest in the two accounts together

9 years agoshe earned a total on the investements $1656.25

9 years agoright. so what is the expression? 50,000 - x is the amount of money invested in the second bank, if we assume x is the amount invested in the 2.5% account

9 years agowe know that because the total amounts are equal to 50000

9 years agoso x+y = 50000

9 years agoy = 50000 - x

9 years agoand if x is the amount in the first account, 50000 - y is the amount in the 3.75% account

9 years agois that helping?

9 years agoi still dont get it but i think i understand ur saying if both x and y equally to 50000 than if you take away .025 away from that than it will give you the answer correct

9 years agoi need to know how to write it out

9 years agoif she has a total at the end of the year of 1656.25 it is asking how much did she invest in both accounts with one being 0.025 and one being 0.0375 annual interest

9 years agoSince: 1. x + y = 50000 2. .025x + .0375y = 1656.25 We substitute for y in the second equation, using the first. i.e. y = 50000 -x Now substitute for y .025x + .0375 (50000 - x) = 1656.25. .025x + 1875 - .0375x = 1656.25 -.0125x = 1656.25 - 1875 -.0125x = -218.75 x = -218.75/-.0125 x = 17500

9 years agoso looking above, she invested 17,500 in the bank with 2.5% interest rate (also known as .025 interest)

9 years agonow that you've solved for one of the values, you can solve for the other (y) by sticking this result back into either equation

9 years agoso x+5 = 50000

9 years ago*x + y

9 years agosince x = 17500, 17500 + y = 50000

9 years agoy = 32500

9 years agoso she invested 32500 in the second bank

9 years ago(the one with .0375 interest)

9 years agonow the final part is - check the answer. that is, at the end of the year, do those two values give you the correct total earned interest

9 years agoso .025*17500 + 32500*.0375 = 437.50 + 1218.75 = 1656.25

9 years agoso we know it's right

9 years agomake sense?

9 years agokinda

9 years ago