Question

50000-x x is the amount of in $ ann invested in the account that pays 2.5% annual interset

Answer 1

ok what are you trying to solve for?

Answer 2

she invests 50,000 in two interst bearing accounts one pays 2.5 % interst and the second 3.75% at the end of one year the interest ann has earned on these is 1656.25 $ how much she invest in each of the accounts

Answer 3

ok got it!

Answer 4

so what in an interest account, each year you earn the % of interest according to your original investment

Answer 5

so from the first account, she will earn 2.5% of 50,000

Answer 6

from the second account, she will earn 3.75% of 50,000

Answer 7

or sorry, bad first assumption

Answer 8

so we have two equations based on this information:

Answer 9

both involve amounts x and y

Answer 10

we know that .025x + .0375y = 1656.25

Answer 11

that is, the interest earned between the two accounts adds up to 1656.25, and by definition .025 of X is earned, and .0375 of y is earned in that year

Answer 12

the other thing we know is that the total amount she invests is 50,000, so x + y = 50,000

Answer 13

now since you have two variables, and two equations, you can use substitution to solve this

Answer 14

so using the second equation, we know that y = 50,000 - x

Answer 15

i have to give a vebal descritpion of 50000-x

Answer 16

I'm not sure what you mean by verbal description

Answer 17

but we know that 50000 - x is the amount invested in one of the banks

Answer 18

it says give a verbal description of what each of the follwoing expression represetn in the context of the problem letting x=2.5 %. 50,000 is the interest in the two accounts together

Answer 19

she earned a total on the investements $1656.25

Answer 20

right. so what is the expression? 50,000 - x is the amount of money invested in the second bank, if we assume x is the amount invested in the 2.5% account

Answer 21

we know that because the total amounts are equal to 50000

Answer 22

so x+y = 50000

Answer 23

y = 50000 - x

Answer 24

and if x is the amount in the first account, 50000 - y is the amount in the 3.75% account

Answer 25

is that helping?

Answer 26

i still dont get it but i think i understand ur saying if both x and y equally to 50000 than if you take away .025 away from that than it will give you the answer correct

Answer 27

i need to know how to write it out

Answer 28

if she has a total at the end of the year of 1656.25 it is asking how much did she invest in both accounts with one being 0.025 and one being 0.0375 annual interest

Answer 29

Since:
1. x + y = 50000
2. .025x + .0375y = 1656.25
We substitute for y in the second equation, using the first.
i.e. y = 50000 -x
Now substitute for y
.025x + .0375 (50000 - x) = 1656.25.
.025x + 1875 - .0375x = 1656.25
-.0125x = 1656.25 - 1875
-.0125x = -218.75
x = -218.75/-.0125
x = 17500

Answer 30

so looking above, she invested 17,500 in the bank with 2.5% interest rate (also known as .025 interest)

Answer 31

now that you've solved for one of the values, you can solve for the other (y) by sticking this result back into either equation

Answer 32

so x+5 = 50000

Answer 33

*x + y

Answer 34

since x = 17500, 17500 + y = 50000

Answer 35

y = 32500

Answer 36

so she invested 32500 in the second bank

Answer 37

(the one with .0375 interest)

Answer 38

now the final part is - check the answer. that is, at the end of the year, do those two values give you the correct total earned interest

Answer 39

so .025*17500 + 32500*.0375 = 437.50 + 1218.75 = 1656.25

Answer 40

so we know it's right

Answer 41

make sense?

Answer 42

kinda