Ask
your own question, for FREE!
Mathematics
11 Online
Find Three consecutive integers such that the square of the second increased by the third is 43
Still Need Help?
Join the QuestionCove community and study together with friends!
They are 3 consecutive integers. Let the first one be X, the second will be X + 1 and the third will be X + 2. Now, according to the problem statement, the square of the second is (X+1)^2. Increasing this by the third means : \[(x+1)^2+(x+2) \] where (X + 2) is the third number. So, the equation is : \[(x+1)^2 + (x+2) = 43\] Solve it for x, and you can get the three consecutive integers.
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Countless7Echos:
Ah trying out the whole T.V girl drawing :p (I love drawing eyes)
SnowyBreaks:
You ever get the types of dreams where it feels as if you aren't breathing? And w
laylasnii13:
Poem/diary i wrote I Want Out Iu2019m so tired of screaming into walls. Every fight with my mom leaves something broken and itu2019s not just plates or slam
Countless7Echos:
Aye.. I need actually some help on the shading here.. if the light is from above too I just feel something is off.
1 hour ago
11 Replies
6 Medals
1 day ago
6 Replies
0 Medals
2 days ago
13 Replies
3 Medals
4 days ago
19 Replies
3 Medals