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OpenStudy (anonymous):
can u help with my question?
OpenStudy (sandra):
looking at it now
OpenStudy (anonymous):
The mass of the atmosphere is 5.25 * 10 to the exponent 19 kg and that the specific heat capacity of dry air is 1050 joule/ (kg C) how many jouls does it take to raise the temperature of the atmosphere by 2 C ?
OpenStudy (anonymous):
r u still there?
OpenStudy (sandra):
hey yes
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OpenStudy (anonymous):
do u get it?
can u help...?
OpenStudy (sandra):
right ok hmmm, so if the heat capicity of dry air is 1050 joule/(kg C), that means it takes 1050 joulels of energy to raise the temperature one degree C
OpenStudy (anonymous):
ok...
OpenStudy (sandra):
so it would take 5.25x10^19Kg * 1050 joule/KgC = 5.513 X 10^22 joules/C
OpenStudy (sandra):
since you want to raise it 2 degrees, it's 1.10 * 10^20 joules (twice as much)
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OpenStudy (sandra):
2C * 5.513 X 10^22 joules/C = 1.10 X10^20 joules
OpenStudy (sandra):
sorry, x 10^23
OpenStudy (anonymous):
is that the asnwer
OpenStudy (sandra):
well, I feel like that makes sense =). use the calculator though that was in my head
OpenStudy (sandra):
the point is multiple the kg * c * j/kgc = j (the number of joules)
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