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Mathematics 56 Online
OpenStudy (anonymous):

did u get it?

OpenStudy (anonymous):

can u help with my question?

OpenStudy (sandra):

looking at it now

OpenStudy (anonymous):

The mass of the atmosphere is 5.25 * 10 to the exponent 19 kg and that the specific heat capacity of dry air is 1050 joule/ (kg C) how many jouls does it take to raise the temperature of the atmosphere by 2 C ?

OpenStudy (anonymous):

r u still there?

OpenStudy (sandra):

hey yes

OpenStudy (anonymous):

do u get it? can u help...?

OpenStudy (sandra):

right ok hmmm, so if the heat capicity of dry air is 1050 joule/(kg C), that means it takes 1050 joulels of energy to raise the temperature one degree C

OpenStudy (anonymous):

ok...

OpenStudy (sandra):

so it would take 5.25x10^19Kg * 1050 joule/KgC = 5.513 X 10^22 joules/C

OpenStudy (sandra):

since you want to raise it 2 degrees, it's 1.10 * 10^20 joules (twice as much)

OpenStudy (sandra):

2C * 5.513 X 10^22 joules/C = 1.10 X10^20 joules

OpenStudy (sandra):

sorry, x 10^23

OpenStudy (anonymous):

is that the asnwer

OpenStudy (sandra):

well, I feel like that makes sense =). use the calculator though that was in my head

OpenStudy (sandra):

the point is multiple the kg * c * j/kgc = j (the number of joules)

OpenStudy (sandra):

which is the mass * 2 degrees c * heat capacity

OpenStudy (sandra):

which got that answer

OpenStudy (anonymous):

ok thanks

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