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OpenStudy (anonymous):

Ok I have this math problem: 3x^2=4^2+x^2 Can you help me solve for x and show me the steps?

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OpenStudy (anonymous):

OpenStudy (anonymous):

\[3x^2 = 4^2 + x^ 2\]

OpenStudy (anonymous):

right? ok, so there is an x term on either side, luckily they are both the same operation on x

OpenStudy (anonymous):

you should move the x terms to one side, try the getting all the x terms on the left side

OpenStudy (anonymous):

ok if i did that then it would take the [x^2\] from the 3

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OpenStudy (anonymous):

right, so the left side would be 2x^2 = 4^2....

OpenStudy (anonymous):

2x^2 = 4*4 = 2*2*2*2, divide both sides by 2 => x^2 = 2*2*2 => solve for x...

OpenStudy (anonymous):

\[3 x ^{2} = 4^{2}+x^{2} \rightarrow 2x^{2} = 4^{2}\] Then \[ 4^{2}= 16 \rightarrow x^{2} = 8 \right arrow x = \pm 2 \sqrt{2} \]

OpenStudy (anonymous):

[\4^{2} = 16 \rightarrow x^{2} = 8 \rightarrow x = +\] or \[- 2 \sqrt{2}\]

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