Question

what is the value of theta here,,
4sin2theta=0

Answer 1

\[4\times \sin (2\theta) = 0\]

If you divide both sides by 4, you get:
\[\frac{4 \times \sin(2\theta)}{4} = \frac{0}{4}\]

which reduces to
\[\sin (2\theta) = 0\]

Now, what are the values where the sin function can be zero? These values are :

0,\[\pi, 2\pi, 3\pi, 4\pi.....npi\]
where n is a natural number

Thus, \[2\theta = 0, \pi, 2\pi, 3\pi, 4\pi, .... npi\]

You can divide both sides by two to get the answer.