Linear Algebra : Cⁿ(complex number)is a vector space over field R(real number).

Question

anonymous · Answer

can i get some help please .......

anonymous · Answer

what is the question asking to be found about the vector space?

anonymous · Answer

i need proof....

anonymous · Answer

i've only ever bothered proving this as part of a relation to a matrix. I think you have to show it's closed under addition and multiplication and to itself, using z = a +ib with a and b in the reals, show for complex y and z, y+z and y*z are complex. I've only ever bothered showing by relation to the matrix: Z = [a -b] <=> z = a+ib [b a] you then use matrix algebra to show Z <=> z in closure of addition and multiplication

anonymous · Answer

oh and scalar

anonymous · Answer

thank you