Question

How do you solve
x+y+2=6
x-y+2z=7
2x-y-4z=-9 step by step please

Answer 1

you can start off by writing the system in augmented matrix form. Then, solve it by gaussian elimination and back substitution method : )

Answer 2

i dont know how to do that lol can you explain further please i am in algebra 2 and this is very confusing to me

Answer 3

x+y+2-2=6-2
xy=4

Answer 4

An augmented matrix is associated with each linear system like
{█(x+y+2=6@x-y+2z=7@2x-y-4z=-9)┤ . Then the system can be written as {█(x+y =4@x-y+2z=7@2x-y-4z=-9)┤

The matrix associated to this system can be written like that ■(1&1&0@1&-1&2@2&-1&-4) = ■(4@7@-9) to the left of the equal is called the coefficient matrix.

First multiply row 2 by (-1). Then add row 1 to row 2 and replace row 2 with the result.

■(1&1&0@0&2&-2@2&-1&-4) = ■(4@-3@-9) .Multiply row 3 by – ½.

Then add row 1 to row 3 and replace row 3 with the result.

■(1&1&0@0&2&-2@0&3/2&2) = ■(4@-3@9/2) . Multiply row 3 by – 4/3.

Then add row 2 to row 3 and replace row 3 with the result.

■(1&1&0@0&2&-2@0&0&-14/3) = ■(4@-3@-14) . Multiply row 3 by – 3/14.Then multiply row 2 by ½.

Then add row 3 to row 2 and replace row 2 with the result.

■(1&1&0@0&1&0@0&0&1) = ■(4@3/2@3) . Multiply row 1 by –1. Then add row 2 to row 1 and replace row 1 with the result.

■(-1&0&0@0&1&0@0&0&1) = ■(-5/2@3/2@3) . Multiply row 1 by and get the final result. The solution is (5/2, 3/2, 3).

Answer 5

I hope you can 'decode' what I send to you.:) Everything is written as matrix.