I'm having trouble with an inverse function problem in Cal 2:

Find the value of the derivative of the inverse of the function.
Given that f(x)=4^(sqrt(x))-x+3, find f-1'(3).

I can't figure out what to do with the constant raised to the power of sqrt(x)

Question

I'm having trouble with an inverse function problem in Cal 2:

Find the value of the derivative of the inverse of the function.
Given that f(x)=4^(sqrt(x))-x+3, find f-1'(3).

I can't figure out what to do with the constant raised to the power of sqrt(x)

anonymous · Answer

The easiest way to find an inverse of a function is to simply swap the x and the y (or in this case "f(x)") and then solve for f(x).  
Is it this:
$$4^{\sqrt{x}}-x-3=f(x)?$$

or this:

$$4^{\sqrt{x}-x-3}=f(x)?$$

anonymous · Answer

oops I meant +3 not -

anonymous · Answer

Boy that's nastier than it looks.