Question

im not sure how to simplify:
a^3+1/6a^2 X 3a/a^2+a

Answer 1

someone please please please help me i'm not too good with factorising and simplifying, no matter how basic those skills are D:

Answer 2

\[a ^{3}/1+ (1/6)*/(a^2)/1+(3/1)*a/a^2+a/1\]

Create full fractions of each term. Next factor the top and bottom of each term separately. So a^2/1 becomes (a*a)/1. Finally determine if any factor (whether a variable or numeral) appears in all the terms. You should find that only (a/1) is able to factor out. [Corrections welcome.]

Answer 3

thanks but i dont think i wrote the question properly D: sorry
its umm
simplify
a^3+1 3a
________ X ________
6a^2 a^2+a
sorry for the inconvenience. and if its the same thing just call me stupid :)

Answer 4

\[((a^3 +1)/6a^2)*(3a/(a^+a)) = (3*(a^3+1))/(6^a^2(a+1))=(3a^3+3)/(6a^3+6)=1/2*(a^3+1)\]

i think this is the ans. go each step by urself to understand it.

Answer 5

\frac{{\mathrm{(}}{a}^{3}\mathrm{{+}}{1}{\mathrm{)(}}{3}{\mathrm{)(}}{a}{\mathrm{)}}}{{\mathrm{(}}{3}{\mathrm{)(}}{2}{\mathrm{)(}}{a}{\mathrm{)(}}{a}{\mathrm{)[}}{a}{\mathrm{(}}{a}\mathrm{{+}}{1}{\mathrm{)]}}}\mathrm{{=}}\frac{{3}{a}{\mathrm{[(}}{a}^{3}\mathrm{{+}}{1}{\mathrm{)]}}}{{3}{a}{\mathrm{(}}{2}{a}{\mathrm{)(}}{a}^{2}\mathrm{{+}}{a}{\mathrm{)}}}

Answer 6

\[{{(a^{3}+1)(3)(a)}\over{(3)(2)(a)(a)[a(a+1)]}}={{3a[(a^{3}+1)]}\over{3a(2a)(a^{2}+a)}}\]
Blah -trying to learn to post in TeX.

Answer 7

Ok - canceling the common term 3a top and bottom - the remultiplying, I get:
\[{{[(a^{3}+1)]}\over{(2a^{3}+2a^{2})}}\]
... if I've read your equation correctly.

Answer 8

moss's bro you are entirely right!
i made a mistake with typing on the TeX

the last step you can also put like


\[1/2 * ([a^3+1]/[a^3+a^2])\]

Answer 9

Cool. BTW, I'm using two helper programs to cut and paste proper TeX equations. One is a visual editor (MathMagic) - useful.

Answer 10

D: i don't know where i went wrong
my answer ended up being
\[a^{2}-a+1\]
______________
\[2a ^{2}\]
any ideas on what im doing wrong?

Answer 11

No I can't really see how you got the trinomial on the top. Can you post your intermediate steps? BTW type "\frac{a+b){a^2} in the Equation editor to compose the fraction a+b)/a^2 for example.