Question

how can i draw a graph of mod(y)=cosx ???

Answer 1

hello high

Answer 2

well, mod(y)=cosx is really two separate graphs (well, the same graph, but there are two distinct parts.)

Answer 3

i think itll look like bubbles

Answer 4

am not so sure...

Answer 5

Are you sure that's a correct problem? What is `mod'?

Answer 6

modulus..

Answer 7

!y!

Answer 8

Yeah sorry. I've never seen mod used that way :)

Answer 9

So you're right if you mean bubbles as in just the parts where cos is above the x axis.

Answer 10

Because the absolute value (or modulus) of y must be positive, by definition, this function isn't defined if y < 0. Since cos(x) is sometimes negative, those parts of the cos(x) plot are not valid for this particular function, because they don't make any sense.

Answer 11

I am wrong!

Answer 12

i think so

Answer 13

Ah, I see what you mean about bubbles now. Yes, I think you're correct.

Answer 14

Because negative values of y will mirror the positive values.

Answer 15

will you please explain?

Answer 16

Well, basically, what the above function means is really two different functions:

\[y = \left\{\begin{align}\cos x\text{ when }y >= 0\\\cos y\text{ when }y < 0\end{align}\right.\]

Answer 17

Hm. Sorry:

\[y = \left\{\begin{matrix}\cos x\text{ when }y >= 0\\\cos x\text{ when }y < 0\end{matrix}\right.\]

Answer 18

The function only exists for cos x > 0, because absolute values cannot be negative. There will be two functions:
y = cos x
-y = cos x

so for each x (when cos x >0),
you will have two values - one positive and other negative, both having the same absolute numerical value

Answer 19

take an example:

let x be \[\frac{\pi}{2}\]
now, y = \[\frac{1}{\sqrt(2)}\]
and -y = \[\frac{1}{\sqrt(2)}\]

So, we put those two together in the same graph.