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OpenStudy (anonymous):
how do i integrate Sin(x)Cos(x)^2
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OpenStudy (anonymous):
for this problem you need to use u substitution
OpenStudy (anonymous):
i thought so
OpenStudy (anonymous):
so should i set u=cosx^2 and du=-2sinx
OpenStudy (anonymous):
let \[u=\cos (x)\] so: \[du=-\sin(x) dx\]
OpenStudy (anonymous):
but its cos(x)^2
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OpenStudy (anonymous):
\[\int\limits_{}^{} \sin(x) \cos^{2}(x) dx=-\int\limits_{}^{} u ^{2} du=-u^3/3=-(1/3)\cos^3(x)\]
OpenStudy (anonymous):
+C
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
no problem
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