how would you simplify a cubed root radical of 25 times the radical of 125
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OpenStudy (anonymous):
ok, you have 25^(1/3) * 125^(1/2)?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
ok, so how are 25 and 125 related?
OpenStudy (anonymous):
Both divisible by 5 and 25?
OpenStudy (anonymous):
ok, cool, so 25 = 5^2 and 125 = 5^2
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OpenStudy (anonymous):
5^3, sorry
OpenStudy (anonymous):
oh okay yeah
OpenStudy (anonymous):
\[\sqrt[3]{25} \times \sqrt{125} = 25^{1/3} \times 125^{1/2} = 5^{2/3} \times 5^{3/2} = 5^{4/6} \times 5^{9/6} = 5^{13/6}\]
Feel free to correct me, this is my first time using this equation maker.
OpenStudy (anonymous):
omg it's too long for the page HAHA
OpenStudy (anonymous):
what is the equation maker?
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OpenStudy (anonymous):
all right
OpenStudy (anonymous):
the answer is 5^{13/6} sorry it's too long haha
OpenStudy (anonymous):
yeah, that's how to do it easily hrwhyhry
OpenStudy (anonymous):
okay.. how on earth did you get that though?
OpenStudy (anonymous):
so you have 25=5^2, and 125=5^3....so you have (5^2)^(1/3) * (5^3)^(1/2)
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OpenStudy (anonymous):
you can then add the exponents...here: \[(5^2)^(1/3)\]
OpenStudy (anonymous):
ohhhhh oka
OpenStudy (anonymous):
y
mn
OpenStudy (anonymous):
(5^2)^(1/3) --> the square (2) and the (1/3) and now add together, 2/3
OpenStudy (anonymous):
okay thank you so much!
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OpenStudy (anonymous):
so, you got it?
OpenStudy (anonymous):
i think soooo
OpenStudy (anonymous):
now how would you do x-\[\sqrt[3]{3}\div \sqrt{12}\]
OpenStudy (anonymous):
sorry its supposed to be the x- the 3 one
OpenStudy (anonymous):
????
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OpenStudy (anonymous):
just a second
OpenStudy (anonymous):
thank you :)
OpenStudy (anonymous):
\[(x-\sqrt[3]{3})/\sqrt{12}\]
OpenStudy (anonymous):
is that the problem? is it equal to something?
OpenStudy (anonymous):
no thats the problem. You only have to simplify it
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so what is sqrt(12)?
OpenStudy (anonymous):
what are factors of 12?
OpenStudy (anonymous):
the square root of 4 times the square root of 3?
OpenStudy (anonymous):
right on, so sqrt(4) is simple, sqrt(3) is good because the problem has 3^(1/3)
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OpenStudy (anonymous):
is the answer 1 over x^1/6 times 2?
OpenStudy (anonymous):
1/(x^1/6 * 2)?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
\[(x-(3^{1/3}))/(2*(3^{1/2}))\]
OpenStudy (anonymous):
i had that... i just dont kmow if u can get rid of the three
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OpenStudy (anonymous):
so you can separate x and -3^(1/3) because they have the same denominator and they are part of a subtraction operation
OpenStudy (anonymous):
ok...
OpenStudy (anonymous):
thank u for the help by the way
OpenStudy (anonymous):
first look at 3^(1/3) / (2 * (3^1/2))
OpenStudy (anonymous):
np
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OpenStudy (anonymous):
can you simplify that? focus on the 3's
OpenStudy (anonymous):
u can divide 3 by 3 and get one right
OpenStudy (anonymous):
when you divide by exponents you and subtract the exponents from values with the same base
OpenStudy (anonymous):
so 3^(1/3) / 3^(1/2) is 3^(1/3) * 3^-(1/2)...can you can add these exponents --> 1/3 = 2/6, 1/2 = 3/6, need to have similar fractions....so 2/6 - 3/6 = -1/6
OpenStudy (anonymous):
so you have 3^(-1/6)
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OpenStudy (anonymous):
which is 1/(3^1/6)
OpenStudy (anonymous):
yes and u have to bring it below the division sign since it is negative?>
OpenStudy (anonymous):
yeah, like in the last message
OpenStudy (anonymous):
is the answer x over 3^1/6 *2
OpenStudy (anonymous):
wait, x-1
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