Find the length of the curve given by
r (t) = ((2^0.5)/2) t)i+(e^t/2)j+(e^−t/2)k,
where −2 =

Question

Find the length of the curve given by
r (t) =   ((2^0.5)/2) t)i+(e^t/2)j+(e^−t/2)k,
where −2 =< t =< 7.

anonymous · Answer

okay - so let me take a shot at it.

Since you are given a function r(t) in terms of all vector component, what needs to be done is to take partial derivatives of each components in terms of t.  Then square each terms and add them, put the sum of squared partials under square root and integrate over the range of t then that should be the length of your curve.

anonymous · Answer

i did that and got ((1/2)+(1/4)e^t+(1/4)e^-t )^(1/2) so i have to integrate that.

anonymous · Answer

that would be something like...
$$s = \int\limits_{t_{i}}^{t_{f}} \sqrt((\delta x/\delta t)^2 + (\delta y/\delta t)^2 + (\delta z/\delta t)^2)) dt$$

anonymous · Answer

something along this line

anonymous · Answer

be sure that dt is not under square roots