Mathematics 34 Online
OpenStudy (anonymous):

Find the volume of the solid that results when the region enclosed by y=x^1/2, y=0, and x=121 is revolved about the line y=121

OpenStudy (swilliams):

What we have here basically is two revolutions, so we can subtract the volume of the inner from the outer to get the final answer. To find the volume of each, we just integrate the area of the circle (pi * r ^ 2) over our interval (in this case from x=0, since sqrt(x) is not real where x < 0, to the given x=121). So with subtracting/simplifying: $V = \pi \int\limits\limits\limits_{0}^{121}R_{outer}(x)^2 - R_{inner}(x)^2dx$ Where R(x) is the radius as a function of x. The radius of the outer circle is going to be (121 - 0), or 121, the distance between y=0 and the axis of revolution. The radius of the inner revolution, then, is going to be (121 - sqrt(x)). If we plug these into our equation, we get: $V = \pi \int\limits\limits\limits\limits_{0}^{121}121^2 - (121 - \sqrt{x})^2dx$ So V equals about 651610.8823.

OpenStudy (anonymous):

Thank you so much. : ) I see where I went wrong in my work. For some reason I put my limits from 0 to 11 instead of 0 to 121. Thanks again.

Latest Questions
Tbone: Edits ^-^
3 hours ago 4 Replies 1 Medal
rose12345: look
3 hours ago 11 Replies 3 Medals
jessii: What are the pros and cons of being a flight attendant?
1 hour ago 4 Replies 0 Medals
SamRoman: What do y'all think of my Cover photo for my next YouTube video?
4 hours ago 11 Replies 1 Medal
lovelygirl13: i made a collage of the color green
1 hour ago 4 Replies 1 Medal
chrishale13840: would this be a good tattoo
7 hours ago 18 Replies 5 Medals
rose12345: helpppppp
9 hours ago 4 Replies 1 Medal