Question

integrate x^2/(x^2+1)^2

Answer 1

i would do partial fractions

Answer 2

x^2 / ( (x^2 + 1) ( x^2 + 1)) , the denominator are irreducible quadratics

Answer 3

x^2 / ( (x^2 + 1) ( x^2 + 1)) = ( A x + b ) / (x^2 + 1) + (Cx + D ) / ( X^2 + 1)^2

Answer 4

x^2 = (Ax+b)(x^2 + 1) + Cx + d
x^2 = Ax^2 + bX^2 + Ax + B + CX + D
x^2 = Ax^3 + Bx^2 + (A + C) x + B + D
so 1x^2 = Bx^2 so B=1

Answer 5

A = 0 , B=1 , D= -1 , C= 0

Answer 6

so we have
intergral x^2/(x^2+1)^2 = int 1/(x^2 +1) - integral 1 / (x^2 +1)^2
the first integral is an arctan, the second one is ... let methink

Answer 7

hmmm, i hope this isnt circular

Answer 8

nevermind, its faster if you do trig substitution

Answer 9

this freaking website just deleted what i wrote.

Answer 10

very frustrating!!!!