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OpenStudy (anonymous):
find the indicated derivatives f(x)=1/2x+3, y''
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OpenStudy (anonymous):
Just to be sure, is this f(x) = (1/2)x + 3, or f(x) = 1/(2x +3)?
OpenStudy (anonymous):
its f(x)=1/(2x+3)
OpenStudy (anonymous):
well then, we have \[f'(x) = (-1/(2x + 3)^2)\times 2 = -2/(2x+3)^2\] where the multiplication by 2 occurs by the chain rule and then \[f''(x) = (4/(2x+3)^3)\times 2 = 8/(2x+3)^3\]
OpenStudy (anonymous):
ohh okay! thanks so much!
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