Question

25-[2+5y-3(y+2)]=-3(2y-5)-
[5(y-1)-3y+3]

Answer 1

y=7 is what I got, but I just did this in my head, so I might have messed something up.

Answer 2

Whoever wrote this problem had too much time to write parenthesis:
y=-2

Answer 3

I don't know.

Answer 4

I was joking can solve this easy question. Here is the answer.

Answer 5

Now this was _____ (not/a) joke.

Answer 6

Fill in the blanks.

Answer 7

The solution of this question is following:
First we will solve LHS (left hand side)
THAT IS 25-[2+5y-3(y+2)]
25-(2+5y-3y-6)
25-(-4+2y)
25+4-2y
29-2y
Hence the solution of LHS is 29-2y
now we will solve RHS (Right Hand Side)
-3(2y-5)-[5(y-1)-3y+3]
-6y+15-(5y-5-3y+3)
-6y+15-(2y-2)
-6y+15-2y+2
-8y+17
Hence the solution of RHS is -8y+17
So now we will put the solutions in the equation:
29-2y=-8y+17
-2y+8y=17-29
6y=-12
y=-2
Hence the solution of the given equation is -2
THANKS

Answer 8

Correct answer is
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