Question

solve for x: log base 8(x+1)=2/3

Answer 1

so you'll rewrite that as

(the third root of 8) or 2, then square that = x + 1
2^2 = 4 = x + 1
so x = 3

Answer 2

maybe i didnt write it right but its log small 8 (x+1)=2/3 can you explain how to solve that?

Answer 3

the (x+1) is not small right? and it's on the same line as Log?

Answer 4

yeah only the 8 is smaller and a line below the log

Answer 5

Yeah I explained it above

Answer 6

do you move the 8 to the right and put it to the 2/3?

Answer 7

The formula is:
[a ^{k} = x and that can be written as Log base a of x = k

Answer 8

i dont understand how to show my steps

Answer 9

In general, \[\log_{a}c = b \ \ , a^{b} = c \]

Answer 10

So your is
Log base 8 of (x + 1) = 2/3
Therefore it's:
8^(2/3) = x + 1
8 ^ (2/3) = The third root of 8 ( or 2), then you square it ( or 4)!
So you have 4 = x + 1
So x = 3
And yes, that's the same one except it's using a,b, and c instead! ^^

Answer 11

\[\log_{8} x+1 = \frac{2}{3} \ \ , 8^{\frac{2}{3}} = x+1\]
\[8^{\frac{2}{3}} = (\sqrt[3]{8})^2 = 2^2 = 4\]
\[4 = x+1 \ \ , x = 3\]
Sorry if I'm invading, HanhLive; just formatting it so it's easier to read :)

Answer 12

okk thank you i got it