Question

what is the full expansion of (3x+2)^4

Answer 1

rewrite as:
[3x+2]^2 * [3x+2]^2

Answer 2

(9x^2 + 2* 6x + 4) * (9x^2 + 2* 6x + 4)

Answer 3

(9x^2 + 12x + 4) * (9x^2 +12x +4)

Answer 4

now multiply these out

Answer 5

still workin on it.. have to write it out

Answer 6

is it 192x?

Answer 7

cant be

Answer 8

isnt there a chart ypu can use?

Answer 9

no im doin this by hand and calculator

Answer 10

ithink there is a chart first column is combinations second is the first term third column is the 2nd term...sound familiar?

Answer 11

You mean Pascal's triangle? Sorry I can figure out how to use it, but it will take a while, havent used it in a long time

Answer 12

im just gonna finish off

Answer 13

yeah using that

Answer 14

Anyway here's the solution:
\[81x^4 + 108x^3 + 36x^2 + 108x^3 +144x^2 +48x +36x^2+48x+16 = 81x^4 +216x^3 +216x^2 +96x + 16\]

Answer 15

\[81x^4 + 108x^3 + 36x^2 + 108x^3 +144x^2 +48x +36x^2+48x+16 =
81x^4 +216x^3 +216x^2 +96x + 16\]

Answer 16

dang it the whole thing wont show up brb

Answer 17

81x^4 + 108x^3 + 36x^2 + 108x^3 +144x^2 +48x +36x^2+48x+16 =
=81x^4 +216x^3 +216x^2 +96x + 16

Answer 18

that's the final answer, i triple checked my work

Answer 19

ok thanks