how do u find the equation of the tangent line to the curve at the given point:
y=e^x/x, (1,e)

Question

anonymous · Answer

1. Take its derivative:
$$dy/dx = -e ^{x}/x ^{2}  +  e ^{x}/x$$

anonymous · Answer

Substitute x = 1

anonymous · Answer

Whatever value you obtain for dy/dx after the substitution, let that represent your m value for the equation y = mx+c

anonymous · Answer

i got 0 as the slope but then when i plug it in i still get the wrong answer

anonymous · Answer

To solve for the constant 'c', just substitute:
x = 1
y = e
m =dy/dx (Its numerical value that you obtained)
Then, for your final sub in the c and m values

anonymous · Answer

Double check to make sure my derivative is correct

anonymous · Answer

But i'm quite sure the steps are correct though.

anonymous · Answer

ok i got it thanks

anonymous · Answer

Using the derivative presented above, I also get 0 as it's derivative at x=1.  If this is the case then the equation of the tangent line at the point (1,e) on the original curve should be y=e.