Question

have to integrate (1/.2s+10)ds They get 5ln(.2s+10)-5ln10. Having limits of 0 and S. How did they get that?

Answer 1

\[\int\limits_{0}^{s}(1/.2)s +10)ds\]?

Answer 2

1/(.2s+10)ds

Answer 3

(.2s+10)=u
du=.2 ds
ds=1/.2=5
\[5\int\limits_{0}^{s}1/u du\]

Answer 4

-- correction
ds=1/.2 du=5du