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y= √ x (x+1) derivatives
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Use the chain rule\[\frac{d}{dx} \sqrt{x(x+1)}=\frac{2x+1}{2 \sqrt{x(x+1)}}\]
1 +1/2x^1/2 would be answer right
If this is your function: \[\sqrt{x(x+1)}\] the derivative is \[\frac{2x+1}{2 \sqrt{x(x+1)}}\] Which is your answer
okay thanks
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